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232423012302113 is a prime number
BaseRepresentation
bin110100110110001100110011…
…000101011111110100100001
31010110221102102100110002221002
4310312030303011133310201
5220431004312122131423
62142153354031241345
766646002625530653
oct6466146305376441
91113842370402832
10232423012302113
116806a056209786
1222099178679255
139c8c51c079329
144157495dd46d3
151bd0cc8b7e228
hexd3633315fd21

232423012302113 has 2 divisors, whose sum is σ = 232423012302114. Its totient is φ = 232423012302112.

The previous prime is 232423012302043. The next prime is 232423012302127. The reversal of 232423012302113 is 311203210324232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201145915838464 + 31277096463649 = 14182592^2 + 5592593^2 .

It is a cyclic number.

It is not a de Polignac number, because 232423012302113 - 212 = 232423012298017 is a prime.

It is a super-3 number, since 3×2324230123021133 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (232423012304113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116211506151056 + 116211506151057.

It is an arithmetic number, because the mean of its divisors is an integer number (116211506151057).

Almost surely, 2232423012302113 is an apocalyptic number.

It is an amenable number.

232423012302113 is a deficient number, since it is larger than the sum of its proper divisors (1).

232423012302113 is an equidigital number, since it uses as much as digits as its factorization.

232423012302113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 232423012302113 its reverse (311203210324232), we get a palindrome (543626222626345).

The spelling of 232423012302113 in words is "two hundred thirty-two trillion, four hundred twenty-three billion, twelve million, three hundred two thousand, one hundred thirteen".