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23243411131 = 533181137867
BaseRepresentation
bin10101101001011010…
…100100111010111011
32012222212120121212221
4111221122210322323
5340100303124011
614402230544511
71451664510013
oct255132447273
965885517787
1023243411131
119948332896
124608208137
132265635815
1411a6d70c43
15910891971
hex5696a4ebb

23243411131 has 8 divisors (see below), whose sum is σ = 23689582704. Its totient is φ = 22797521760.

The previous prime is 23243411129. The next prime is 23243411141. The reversal of 23243411131 is 13111434232.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 23243411131 - 21 = 23243411129 is a prime.

It is a super-2 number, since 2×232434111312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23243411096 and 23243411105.

It is not an unprimeable number, because it can be changed into a prime (23243411141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99660 + ... + 237526.

It is an arithmetic number, because the mean of its divisors is an integer number (2961197838).

Almost surely, 223243411131 is an apocalyptic number.

23243411131 is a deficient number, since it is larger than the sum of its proper divisors (446171573).

23243411131 is a wasteful number, since it uses less digits than its factorization.

23243411131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141101.

The product of its digits is 1728, while the sum is 25.

Adding to 23243411131 its reverse (13111434232), we get a palindrome (36354845363).

The spelling of 23243411131 in words is "twenty-three billion, two hundred forty-three million, four hundred eleven thousand, one hundred thirty-one".

Divisors: 1 53 3181 137867 168593 7306951 438554927 23243411131