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23249135433 = 319577706897
BaseRepresentation
bin10101101001110000…
…011010011101001001
32020000021100110011010
4111221300122131021
5340103234313213
614402553354133
71452064250646
oct255160323511
966007313133
1023249135433
119950592617
12460a108949
13226688b194
1411a7a20dcd
15911122ac3
hex569c1a749

23249135433 has 16 divisors (see below), whose sum is σ = 32686963520. Its totient is φ = 14658195456.

The previous prime is 23249135423. The next prime is 23249135443. The reversal of 23249135433 is 33453194232.

It is an interprime number because it is at equal distance from previous prime (23249135423) and next prime (23249135443).

It is not a de Polignac number, because 23249135433 - 29 = 23249134921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23249135391 and 23249135400.

It is not an unprimeable number, because it can be changed into a prime (23249135423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 320560 + ... + 386337.

It is an arithmetic number, because the mean of its divisors is an integer number (2042935220).

Almost surely, 223249135433 is an apocalyptic number.

It is an amenable number.

23249135433 is a deficient number, since it is larger than the sum of its proper divisors (9437828087).

23249135433 is a wasteful number, since it uses less digits than its factorization.

23249135433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 707496.

The product of its digits is 233280, while the sum is 39.

The spelling of 23249135433 in words is "twenty-three billion, two hundred forty-nine million, one hundred thirty-five thousand, four hundred thirty-three".

Divisors: 1 3 19 57 577 1731 10963 32889 706897 2120691 13431043 40293129 407879569 1223638707 7749711811 23249135433