Base | Representation |
---|---|
bin | 110100110111010110100100… |
… | …010011101000101111111001 |
3 | 1010111012222212120001100011111 |
4 | 310313112210103220233321 |
5 | 220433304022114323213 |
6 | 2142254013530000321 |
7 | 66654505533454606 |
oct | 6467264423505771 |
9 | 1114188776040144 |
10 | 232502221245433 |
11 | 6809a702633207 |
12 | 220b05a35760a1 |
13 | 9c96b3333cb69 |
14 | 415b24ba916ad |
15 | 1bd2db2990a3d |
hex | d375a44e8bf9 |
232502221245433 has 2 divisors, whose sum is σ = 232502221245434. Its totient is φ = 232502221245432.
The previous prime is 232502221245421. The next prime is 232502221245479. The reversal of 232502221245433 is 334542122205232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 231445348835584 + 1056872409849 = 15213328^2 + 1028043^2 .
It is a cyclic number.
It is not a de Polignac number, because 232502221245433 - 29 = 232502221244921 is a prime.
It is not a weakly prime, because it can be changed into another prime (232502221243433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116251110622716 + 116251110622717.
It is an arithmetic number, because the mean of its divisors is an integer number (116251110622717).
Almost surely, 2232502221245433 is an apocalyptic number.
It is an amenable number.
232502221245433 is a deficient number, since it is larger than the sum of its proper divisors (1).
232502221245433 is an equidigital number, since it uses as much as digits as its factorization.
232502221245433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 40.
The spelling of 232502221245433 in words is "two hundred thirty-two trillion, five hundred two billion, two hundred twenty-one million, two hundred forty-five thousand, four hundred thirty-three".
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