Base | Representation |
---|---|
bin | 110100110111010111011011… |
… | …101011110100010111001011 |
3 | 1010111020002021022021210102121 |
4 | 310313113123223310113023 |
5 | 220433312422441100324 |
6 | 2142254250035312111 |
7 | 66654540544534066 |
oct | 6467273353642713 |
9 | 1114202238253377 |
10 | 232503150331339 |
11 | 680a003a0211a8 |
12 | 220b080274b637 |
13 | 9c96c5097b434 |
14 | 415b2d921d8dd |
15 | 1bd2e193155e4 |
hex | d375dbaf45cb |
232503150331339 has 2 divisors, whose sum is σ = 232503150331340. Its totient is φ = 232503150331338.
The previous prime is 232503150331217. The next prime is 232503150331379. The reversal of 232503150331339 is 933133051305232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232503150331339 - 217 = 232503150200267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 232503150331295 and 232503150331304.
It is not a weakly prime, because it can be changed into another prime (232503150331379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116251575165669 + 116251575165670.
It is an arithmetic number, because the mean of its divisors is an integer number (116251575165670).
Almost surely, 2232503150331339 is an apocalyptic number.
232503150331339 is a deficient number, since it is larger than the sum of its proper divisors (1).
232503150331339 is an equidigital number, since it uses as much as digits as its factorization.
232503150331339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 656100, while the sum is 43.
The spelling of 232503150331339 in words is "two hundred thirty-two trillion, five hundred three billion, one hundred fifty million, three hundred thirty-one thousand, three hundred thirty-nine".
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