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2325143121434 = 27166081651531
BaseRepresentation
bin100001110101011101010…
…101000110111000011010
322020021121012222210012222
4201311131111012320122
5301043343114341214
64540053410304042
7326662133302430
oct41653525067032
98207535883188
102325143121434
118170a6748391
12316765888022
1313b34c45a513
1480774d92d50
1540737bd038e
hex21d5d546e1a

2325143121434 has 8 divisors (see below), whose sum is σ = 3985959636768. Its totient is φ = 996489909180.

The previous prime is 2325143121407. The next prime is 2325143121463. The reversal of 2325143121434 is 4341213415232.

2325143121434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 2325143121394 and 2325143121403.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83040825752 + ... + 83040825779.

It is an arithmetic number, because the mean of its divisors is an integer number (498244954596).

Almost surely, 22325143121434 is an apocalyptic number.

2325143121434 is a deficient number, since it is larger than the sum of its proper divisors (1660816515334).

2325143121434 is a wasteful number, since it uses less digits than its factorization.

2325143121434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 166081651540.

The product of its digits is 69120, while the sum is 35.

Adding to 2325143121434 its reverse (4341213415232), we get a palindrome (6666356536666).

The spelling of 2325143121434 in words is "two trillion, three hundred twenty-five billion, one hundred forty-three million, one hundred twenty-one thousand, four hundred thirty-four".

Divisors: 1 2 7 14 166081651531 332163303062 1162571560717 2325143121434