Base | Representation |
---|---|
bin | 110100110111111010101110… |
… | …010101101001010111000011 |
3 | 1010111100201002012101022112102 |
4 | 310313322232111221113003 |
5 | 220434423024312000201 |
6 | 2142323514141421015 |
7 | 66660351566532155 |
oct | 6467725625512703 |
9 | 1114321065338472 |
10 | 232541044250051 |
11 | 68105115168199 |
12 | 220b801926a76b |
13 | 9c9a6ac5c3b44 |
14 | 415d091bdaad5 |
15 | 1bd3dd5e8326b |
hex | d37eae5695c3 |
232541044250051 has 2 divisors, whose sum is σ = 232541044250052. Its totient is φ = 232541044250050.
The previous prime is 232541044250041. The next prime is 232541044250057. The reversal of 232541044250051 is 150052440145232.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-232541044250051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 232541044249987 and 232541044250014.
It is not a weakly prime, because it can be changed into another prime (232541044250057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116270522125025 + 116270522125026.
It is an arithmetic number, because the mean of its divisors is an integer number (116270522125026).
Almost surely, 2232541044250051 is an apocalyptic number.
232541044250051 is a deficient number, since it is larger than the sum of its proper divisors (1).
232541044250051 is an equidigital number, since it uses as much as digits as its factorization.
232541044250051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 232541044250051 its reverse (150052440145232), we get a palindrome (382593484395283).
The spelling of 232541044250051 in words is "two hundred thirty-two trillion, five hundred forty-one billion, forty-four million, two hundred fifty thousand, fifty-one".
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