Base | Representation |
---|---|
bin | 110100110111111010111010… |
… | …000100010110001001100011 |
3 | 1010111100201120220200100122212 |
4 | 310313322322010112021203 |
5 | 220434423430201312012 |
6 | 2142323545451352335 |
7 | 66660356506324166 |
oct | 6467727204261143 |
9 | 1114321526610585 |
10 | 232541241041507 |
11 | 68105206259562 |
12 | 220b80731526ab |
13 | 9c9a7112c68a8 |
14 | 415d0addc5add |
15 | 1bd3de83a6b22 |
hex | d37eba116263 |
232541241041507 has 2 divisors, whose sum is σ = 232541241041508. Its totient is φ = 232541241041506.
The previous prime is 232541241041497. The next prime is 232541241041521. The reversal of 232541241041507 is 705140142145232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 232541241041507 - 226 = 232541173932643 is a prime.
It is not a weakly prime, because it can be changed into another prime (232541241041537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116270620520753 + 116270620520754.
It is an arithmetic number, because the mean of its divisors is an integer number (116270620520754).
Almost surely, 2232541241041507 is an apocalyptic number.
232541241041507 is a deficient number, since it is larger than the sum of its proper divisors (1).
232541241041507 is an equidigital number, since it uses as much as digits as its factorization.
232541241041507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 268800, while the sum is 41.
Adding to 232541241041507 its reverse (705140142145232), we get a palindrome (937681383186739).
The spelling of 232541241041507 in words is "two hundred thirty-two trillion, five hundred forty-one billion, two hundred forty-one million, forty-one thousand, five hundred seven".
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