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232802466433 is a prime number
BaseRepresentation
bin1101100011010000011…
…0111011101010000001
3211020220101220122002121
43120310012323222001
512303234412411213
6254540432444241
722551030212635
oct3306406735201
9736811818077
10232802466433
118a804a17799
12391510a9681
1318c51196024
14b3a67d2dc5
1560c812388d
hex36341bba81

232802466433 has 2 divisors, whose sum is σ = 232802466434. Its totient is φ = 232802466432.

The previous prime is 232802466401. The next prime is 232802466437. The reversal of 232802466433 is 334664208232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 170393932944 + 62408533489 = 412788^2 + 249817^2 .

It is a cyclic number.

It is not a de Polignac number, because 232802466433 - 25 = 232802466401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 232802466433.

It is not a weakly prime, because it can be changed into another prime (232802466437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116401233216 + 116401233217.

It is an arithmetic number, because the mean of its divisors is an integer number (116401233217).

Almost surely, 2232802466433 is an apocalyptic number.

It is an amenable number.

232802466433 is a deficient number, since it is larger than the sum of its proper divisors (1).

232802466433 is an equidigital number, since it uses as much as digits as its factorization.

232802466433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 995328, while the sum is 43.

The spelling of 232802466433 in words is "two hundred thirty-two billion, eight hundred two million, four hundred sixty-six thousand, four hundred thirty-three".