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233004415002041 is a prime number
BaseRepresentation
bin110100111110101010010001…
…011000110010010110111001
31010120000000010022012102201202
4310332222101120302112321
5221020021020220031131
62143320430041023545
7100036004421121154
oct6476522130622671
91116000108172652
10233004415002041
11682736879464a1
1222171997184bb5
13a0022b6b14567
14417768c3a8c9b
151be0ea5eaabcb
hexd3ea916325b9

233004415002041 has 2 divisors, whose sum is σ = 233004415002042. Its totient is φ = 233004415002040.

The previous prime is 233004415001999. The next prime is 233004415002067. The reversal of 233004415002041 is 140200514400332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 218473231105600 + 14531183896441 = 14780840^2 + 3811979^2 .

It is a cyclic number.

It is not a de Polignac number, because 233004415002041 - 222 = 233004410807737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 233004415001995 and 233004415002013.

It is not a weakly prime, because it can be changed into another prime (233004415002341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116502207501020 + 116502207501021.

It is an arithmetic number, because the mean of its divisors is an integer number (116502207501021).

Almost surely, 2233004415002041 is an apocalyptic number.

It is an amenable number.

233004415002041 is a deficient number, since it is larger than the sum of its proper divisors (1).

233004415002041 is an equidigital number, since it uses as much as digits as its factorization.

233004415002041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 233004415002041 its reverse (140200514400332), we get a palindrome (373204929402373).

The spelling of 233004415002041 in words is "two hundred thirty-three trillion, four billion, four hundred fifteen million, two thousand, forty-one".