Base | Representation |
---|---|
bin | 100001111010010110110… |
… | …010001001000011101011 |
3 | 22020210011201111112222002 |
4 | 201322112302021003223 |
5 | 301140130403014011 |
6 | 4542323310321215 |
7 | 330236351114261 |
oct | 41722662110353 |
9 | 8223151445862 |
10 | 2330402001131 |
11 | 8193551a3556 |
12 | 317792ab920b |
13 | 13b9a9b1a459 |
14 | 80b135a2431 |
15 | 40944721c3b |
hex | 21e96c890eb |
2330402001131 has 8 divisors (see below), whose sum is σ = 2408632925184. Its totient is φ = 2252362118760.
The previous prime is 2330402001121. The next prime is 2330402001149. The reversal of 2330402001131 is 1311002040332.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2330402001131 is a prime.
It is a super-2 number, since 2×23304020011312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2330402001121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47735615 + ... + 47784408.
It is an arithmetic number, because the mean of its divisors is an integer number (301079115648).
Almost surely, 22330402001131 is an apocalyptic number.
2330402001131 is a deficient number, since it is larger than the sum of its proper divisors (78230924053).
2330402001131 is an equidigital number, since it uses as much as digits as its factorization.
2330402001131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95520841.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2330402001131 its reverse (1311002040332), we get a palindrome (3641404041463).
The spelling of 2330402001131 in words is "two trillion, three hundred thirty billion, four hundred two million, one thousand, one hundred thirty-one".
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