Base | Representation |
---|---|
bin | 100001111010010110111… |
… | …010001100100000010001 |
3 | 22020210011212110211002021 |
4 | 201322112322030200101 |
5 | 301140131423044101 |
6 | 4542323423451441 |
7 | 330236405056501 |
oct | 41722672144021 |
9 | 8223155424067 |
10 | 2330404112401 |
11 | 819356405802 |
12 | 317793756b81 |
13 | 13b9aa3a9421 |
14 | 80b13991a01 |
15 | 409449dc5a1 |
hex | 21e96e8c811 |
2330404112401 has 4 divisors (see below), whose sum is σ = 2330412585712. Its totient is φ = 2330395639092.
The previous prime is 2330404112363. The next prime is 2330404112431. The reversal of 2330404112401 is 1042114040332.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2330404112401 - 235 = 2296044374033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2330404112431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3809775 + ... + 4378948.
It is an arithmetic number, because the mean of its divisors is an integer number (582603146428).
Almost surely, 22330404112401 is an apocalyptic number.
It is an amenable number.
2330404112401 is a deficient number, since it is larger than the sum of its proper divisors (8473311).
2330404112401 is an equidigital number, since it uses as much as digits as its factorization.
2330404112401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8473310.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2330404112401 its reverse (1042114040332), we get a palindrome (3372518152733).
The spelling of 2330404112401 in words is "two trillion, three hundred thirty billion, four hundred four million, one hundred twelve thousand, four hundred one".
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