Base | Representation |
---|---|
bin | 1010100110001111010011… |
… | …10011110001110011100001 |
3 | 10001111212000012121222002011 |
4 | 11103013221303301303201 |
5 | 11023303314240323343 |
6 | 121321433125552521 |
7 | 4623444552510664 |
oct | 523075163616341 |
9 | 101455005558064 |
10 | 23304120245473 |
11 | 7475249383461 |
12 | 27445b2875741 |
13 | 10007524457c2 |
14 | 5a7cd558b6db |
15 | 2a62d886229d |
hex | 1531e9cf1ce1 |
23304120245473 has 2 divisors, whose sum is σ = 23304120245474. Its totient is φ = 23304120245472.
The previous prime is 23304120245459. The next prime is 23304120245521. The reversal of 23304120245473 is 37454202140332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14556414892369 + 8747705353104 = 3815287^2 + 2957652^2 .
It is a cyclic number.
It is not a de Polignac number, because 23304120245473 - 233 = 23295530310881 is a prime.
It is not a weakly prime, because it can be changed into another prime (23304120245423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11652060122736 + 11652060122737.
It is an arithmetic number, because the mean of its divisors is an integer number (11652060122737).
Almost surely, 223304120245473 is an apocalyptic number.
It is an amenable number.
23304120245473 is a deficient number, since it is larger than the sum of its proper divisors (1).
23304120245473 is an equidigital number, since it uses as much as digits as its factorization.
23304120245473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 40.
The spelling of 23304120245473 in words is "twenty-three trillion, three hundred four billion, one hundred twenty million, two hundred forty-five thousand, four hundred seventy-three".
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