Base | Representation |
---|---|
bin | 100001111010111100111… |
… | …001010000011001010011 |
3 | 22020211211021122101212121 |
4 | 201322330321100121103 |
5 | 301142433044303103 |
6 | 4542510551035111 |
7 | 330261243660142 |
oct | 41727471203123 |
9 | 8224737571777 |
10 | 2331041400403 |
11 | 819653111701 |
12 | 31793106ba97 |
13 | 13ba7c42c311 |
14 | 80b74483759 |
15 | 409809236bd |
hex | 21ebce50653 |
2331041400403 has 2 divisors, whose sum is σ = 2331041400404. Its totient is φ = 2331041400402.
The previous prime is 2331041400397. The next prime is 2331041400419. The reversal of 2331041400403 is 3040041401332.
2331041400403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2331041400403 - 217 = 2331041269331 is a prime.
It is not a weakly prime, because it can be changed into another prime (2331041400433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165520700201 + 1165520700202.
It is an arithmetic number, because the mean of its divisors is an integer number (1165520700202).
Almost surely, 22331041400403 is an apocalyptic number.
2331041400403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2331041400403 is an equidigital number, since it uses as much as digits as its factorization.
2331041400403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 2331041400403 its reverse (3040041401332), we get a palindrome (5371082801735).
The spelling of 2331041400403 in words is "two trillion, three hundred thirty-one billion, forty-one million, four hundred thousand, four hundred three".
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