Base | Representation |
---|---|
bin | 100001111011000001001… |
… | …010100000011001001001 |
3 | 22020212000021102121220121 |
4 | 201323001022200121021 |
5 | 301143104413444431 |
6 | 4542522030223241 |
7 | 330263103555331 |
oct | 41730112403111 |
9 | 8225007377817 |
10 | 2331113031241 |
11 | 81968a596a45 |
12 | 317951054b21 |
13 | 13ba9121c227 |
14 | 80b7dbac0c1 |
15 | 40986d72611 |
hex | 21ec12a0649 |
2331113031241 has 4 divisors (see below), whose sum is σ = 2453803190800. Its totient is φ = 2208422871684.
The previous prime is 2331113031229. The next prime is 2331113031251. The reversal of 2331113031241 is 1421303111332.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2331113031241 - 229 = 2330576160329 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2331113031211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61345079751 + ... + 61345079788.
It is an arithmetic number, because the mean of its divisors is an integer number (613450797700).
Almost surely, 22331113031241 is an apocalyptic number.
It is an amenable number.
2331113031241 is a deficient number, since it is larger than the sum of its proper divisors (122690159559).
2331113031241 is a wasteful number, since it uses less digits than its factorization.
2331113031241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 122690159558.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 2331113031241 its reverse (1421303111332), we get a palindrome (3752416142573).
The spelling of 2331113031241 in words is "two trillion, three hundred thirty-one billion, one hundred thirteen million, thirty-one thousand, two hundred forty-one".
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