Search a number
-
+
23312041320434 = 211656020660217
BaseRepresentation
bin1010100110011110000011…
…11100010001111111110010
310001112121110020112021011212
411103033001330101333302
511023421030034223214
6121325223130040122
74624145054522666
oct523170174217762
9101477406467155
1023312041320434
1174786436442a9
122746043579042
1310014155138c9
145a844758c8a6
152a65ede6c53e
hex1533c1f11ff2

23312041320434 has 4 divisors (see below), whose sum is σ = 34968061980654. Its totient is φ = 11656020660216.

The previous prime is 23312041320361. The next prime is 23312041320443. The reversal of 23312041320434 is 43402314021332.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 14211580530625 + 9100460789809 = 3769825^2 + 3016697^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 23312041320434.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5828010330107 + ... + 5828010330110.

Almost surely, 223312041320434 is an apocalyptic number.

23312041320434 is a deficient number, since it is larger than the sum of its proper divisors (11656020660220).

23312041320434 is a wasteful number, since it uses less digits than its factorization.

23312041320434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11656020660219.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 23312041320434 its reverse (43402314021332), we get a palindrome (66714355341766).

The spelling of 23312041320434 in words is "twenty-three trillion, three hundred twelve billion, forty-one million, three hundred twenty thousand, four hundred thirty-four".

Divisors: 1 2 11656020660217 23312041320434