Base | Representation |
---|---|
bin | 110101000000011111100001… |
… | …011000011010011111001011 |
3 | 1010120110001002012222112112202 |
4 | 311000133201120122133023 |
5 | 221024101334122230011 |
6 | 2143454330400030415 |
7 | 100051052303434136 |
oct | 6500374130323713 |
9 | 1116401065875482 |
10 | 233130311133131 |
11 | 68312011a38125 |
12 | 2219227160240b |
13 | a01112b6cab99 |
14 | 417d7d280321d |
15 | 1be43c38cd23b |
hex | d407e161a7cb |
233130311133131 has 4 divisors (see below), whose sum is σ = 233131349481000. Its totient is φ = 233129272785264.
The previous prime is 233130311133119. The next prime is 233130311133157. The reversal of 233130311133131 is 131331113031332.
233130311133131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 233130311133131 - 210 = 233130311132107 is a prime.
It is a super-3 number, since 3×2331303111331313 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 233130311133094 and 233130311133103.
It is not an unprimeable number, because it can be changed into a prime (233130311133431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518837081 + ... + 519286218.
It is an arithmetic number, because the mean of its divisors is an integer number (58282837370250).
Almost surely, 2233130311133131 is an apocalyptic number.
233130311133131 is a deficient number, since it is larger than the sum of its proper divisors (1038347869).
233130311133131 is a wasteful number, since it uses less digits than its factorization.
233130311133131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1038347868.
The product of its (nonzero) digits is 4374, while the sum is 29.
Adding to 233130311133131 its reverse (131331113031332), we get a palindrome (364461424164463).
The spelling of 233130311133131 in words is "two hundred thirty-three trillion, one hundred thirty billion, three hundred eleven million, one hundred thirty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.089 sec. • engine limits •