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233130404041 is a prime number
BaseRepresentation
bin1101100100011110100…
…1111010100011001001
3211021202020222120220221
43121013221322203021
512304422340412131
6255033145350041
722562121511153
oct3310751724311
9737666876827
10233130404041
118a963043107
1239222a98321
1318ca40c6152
14b3d8199ad3
1560e6d00411
hex3647a7a8c9

233130404041 has 2 divisors, whose sum is σ = 233130404042. Its totient is φ = 233130404040.

The previous prime is 233130404027. The next prime is 233130404051. The reversal of 233130404041 is 140404031332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 230420160441 + 2710243600 = 480021^2 + 52060^2 .

It is a cyclic number.

It is not a de Polignac number, because 233130404041 - 233 = 224540469449 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 233130403997 and 233130404015.

It is not a weakly prime, because it can be changed into another prime (233130404011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116565202020 + 116565202021.

It is an arithmetic number, because the mean of its divisors is an integer number (116565202021).

Almost surely, 2233130404041 is an apocalyptic number.

It is an amenable number.

233130404041 is a deficient number, since it is larger than the sum of its proper divisors (1).

233130404041 is an equidigital number, since it uses as much as digits as its factorization.

233130404041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 233130404041 its reverse (140404031332), we get a palindrome (373534435373).

The spelling of 233130404041 in words is "two hundred thirty-three billion, one hundred thirty million, four hundred four thousand, forty-one".