2331312010041 has 8 divisors (see below), whose sum is σ = 3552475443904. Its totient is φ = 1332178291440.

The previous prime is 2331312010009. The next prime is 2331312010067. The reversal of 2331312010041 is 1400102131332.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2331312010041 - 2⁵ = 2331312010009 is a prime.

It is a super-4 number, since 4×2331312010041⁴ (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 111014857621 = 2331312010041 / (2 + 3 + 3 + 1 + 3 + 1 + 2 + 0 + 1 + 0 + 0 + 4 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2331312010091) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55507428790 + ... + 55507428831.

It is an arithmetic number, because the mean of its divisors is an integer number (444059430488).

Almost surely, 2^{2331312010041} is an apocalyptic number.

2331312010041 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

It is an amenable number.

2331312010041 is a deficient number, since it is larger than the sum of its proper divisors (1221163433863).

2331312010041 is a wasteful number, since it uses less digits than its factorization.

2331312010041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111014857631.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2331312010041 its reverse (1400102131332), we get a palindrome (3731414141373).

The spelling of 2331312010041 in words is "two trillion, three hundred thirty-one billion, three hundred twelve million, ten thousand, forty-one".