Base | Representation |
---|---|
bin | 1010100110100000011011… |
… | …10011111110111001000011 |
3 | 10001112201201221200221010101 |
4 | 11103100031303332321003 |
5 | 11023431131414312233 |
6 | 121325553320343231 |
7 | 4624221442114222 |
oct | 523201563767103 |
9 | 101481657627111 |
10 | 23313314213443 |
11 | 74791371076a1 |
12 | 2746339914b17 |
13 | 100158914a637 |
14 | 5a8528654cb9 |
15 | 2a6675aa5c7d |
hex | 15340dcfee43 |
23313314213443 has 2 divisors, whose sum is σ = 23313314213444. Its totient is φ = 23313314213442.
The previous prime is 23313314213437. The next prime is 23313314213467. The reversal of 23313314213443 is 34431241331332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23313314213443 - 241 = 21114290957891 is a prime.
It is a super-2 number, since 2×233133142134432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23313314213843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656657106721 + 11656657106722.
It is an arithmetic number, because the mean of its divisors is an integer number (11656657106722).
Almost surely, 223313314213443 is an apocalyptic number.
23313314213443 is a deficient number, since it is larger than the sum of its proper divisors (1).
23313314213443 is an equidigital number, since it uses as much as digits as its factorization.
23313314213443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 37.
Adding to 23313314213443 its reverse (34431241331332), we get a palindrome (57744555544775).
The spelling of 23313314213443 in words is "twenty-three trillion, three hundred thirteen billion, three hundred fourteen million, two hundred thirteen thousand, four hundred forty-three".
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