Base | Representation |
---|---|
bin | 100001111011010011110… |
… | …101010011101100011011 |
3 | 22020212211002210100100102 |
4 | 201323103311103230123 |
5 | 301144230104210212 |
6 | 4543013055330015 |
7 | 330303626034242 |
oct | 41732365235433 |
9 | 8225732710312 |
10 | 2331426241307 |
11 | 819830373339 |
12 | 317a19b2090b |
13 | 13bb11093a27 |
14 | 80bad61d959 |
15 | 409a45e05c2 |
hex | 21ed3d53b1b |
2331426241307 has 2 divisors, whose sum is σ = 2331426241308. Its totient is φ = 2331426241306.
The previous prime is 2331426241279. The next prime is 2331426241349. The reversal of 2331426241307 is 7031426241332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2331426241307 - 28 = 2331426241051 is a prime.
It is a super-3 number, since 3×23314262413073 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2331426244307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165713120653 + 1165713120654.
It is an arithmetic number, because the mean of its divisors is an integer number (1165713120654).
Almost surely, 22331426241307 is an apocalyptic number.
2331426241307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2331426241307 is an equidigital number, since it uses as much as digits as its factorization.
2331426241307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
The spelling of 2331426241307 in words is "two trillion, three hundred thirty-one billion, four hundred twenty-six million, two hundred forty-one thousand, three hundred seven".
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