Base | Representation |
---|---|
bin | 1010100110100111010110… |
… | …11101000000111100100001 |
3 | 10001120002100002202101001101 |
4 | 11103103223131000330201 |
5 | 11024011240340000442 |
6 | 121331410313234401 |
7 | 4624412544040405 |
oct | 523235335007441 |
9 | 101502302671041 |
10 | 23317032734497 |
11 | 747a775117597 |
12 | 2746bb7102a01 |
13 | 1001a2c657458 |
14 | 5a879c457105 |
15 | 2a67e2279cb7 |
hex | 1534eb740f21 |
23317032734497 has 2 divisors, whose sum is σ = 23317032734498. Its totient is φ = 23317032734496.
The previous prime is 23317032734381. The next prime is 23317032734539. The reversal of 23317032734497 is 79443723071332.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18778390227216 + 4538642507281 = 4333404^2 + 2130409^2 .
It is a cyclic number.
It is not a de Polignac number, because 23317032734497 - 223 = 23317024345889 is a prime.
It is not a weakly prime, because it can be changed into another prime (23317032734797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11658516367248 + 11658516367249.
It is an arithmetic number, because the mean of its divisors is an integer number (11658516367249).
Almost surely, 223317032734497 is an apocalyptic number.
It is an amenable number.
23317032734497 is a deficient number, since it is larger than the sum of its proper divisors (1).
23317032734497 is an equidigital number, since it uses as much as digits as its factorization.
23317032734497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16003008, while the sum is 55.
The spelling of 23317032734497 in words is "twenty-three trillion, three hundred seventeen billion, thirty-two million, seven hundred thirty-four thousand, four hundred ninety-seven".
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