Base | Representation |
---|---|
bin | 1010100110101111010111… |
… | …00101110100111111010001 |
3 | 10001120111102120211200201121 |
4 | 11103113223211310333101 |
5 | 11024044040440341423 |
6 | 121333400543002241 |
7 | 4624624204224520 |
oct | 523275345647721 |
9 | 101514376750647 |
10 | 23321330012113 |
11 | 748157a8958a1 |
12 | 27479b6299381 |
13 | 1002265a32783 |
14 | 5a8a890724b7 |
15 | 2a699467245d |
hex | 1535eb974fd1 |
23321330012113 has 16 divisors (see below), whose sum is σ = 28235614587264. Its totient is φ = 18803949062400.
The previous prime is 23321330012107. The next prime is 23321330012119. The reversal of 23321330012113 is 31121003312332.
It is an interprime number because it is at equal distance from previous prime (23321330012107) and next prime (23321330012119).
It is a cyclic number.
It is not a de Polignac number, because 23321330012113 - 225 = 23321296457681 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23321330012119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51319695 + ... + 51772132.
It is an arithmetic number, because the mean of its divisors is an integer number (1764725911704).
Almost surely, 223321330012113 is an apocalyptic number.
It is an amenable number.
23321330012113 is a deficient number, since it is larger than the sum of its proper divisors (4914284575151).
23321330012113 is a wasteful number, since it uses less digits than its factorization.
23321330012113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103093752.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 23321330012113 its reverse (31121003312332), we get a palindrome (54442333324445).
The spelling of 23321330012113 in words is "twenty-three trillion, three hundred twenty-one billion, three hundred thirty million, twelve thousand, one hundred thirteen".
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