Base | Representation |
---|---|
bin | 10101101110100110… |
… | …011011101010110001 |
3 | 2020012221021101002121 |
4 | 111232212123222301 |
5 | 340240040430131 |
6 | 14415015314241 |
7 | 1454102112406 |
oct | 255646335261 |
9 | 66187241077 |
10 | 23330405041 |
11 | 9992450689 |
12 | 463137b981 |
13 | 227a6743c8 |
14 | 11b47382ad |
15 | 918327911 |
hex | 56e99bab1 |
23330405041 has 4 divisors (see below), whose sum is σ = 24082998784. Its totient is φ = 22577811300.
The previous prime is 23330404991. The next prime is 23330405081. The reversal of 23330405041 is 14050403332.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23330405041 - 221 = 23328307889 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23330404997 and 23330405015.
It is not an unprimeable number, because it can be changed into a prime (23330405081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376296825 + ... + 376296886.
It is an arithmetic number, because the mean of its divisors is an integer number (6020749696).
Almost surely, 223330405041 is an apocalyptic number.
It is an amenable number.
23330405041 is a deficient number, since it is larger than the sum of its proper divisors (752593743).
23330405041 is an equidigital number, since it uses as much as digits as its factorization.
23330405041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 752593742.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 23330405041 its reverse (14050403332), we get a palindrome (37380808373).
The spelling of 23330405041 in words is "twenty-three billion, three hundred thirty million, four hundred five thousand, forty-one".
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