Search a number
-
+
23332465406753 is a prime number
BaseRepresentation
bin1010100111000100000110…
…10011111111001100100001
310001121120011122001100111022
411103202003103333030201
511024234342121004003
6121342441525055225
74625500146430106
oct523420323771441
9101546148040438
1023332465406753
11748627449a688
122749ba3557515
13100331ba14199
145a9423d08aad
152a6de7058738
hex1538834ff321

23332465406753 has 2 divisors, whose sum is σ = 23332465406754. Its totient is φ = 23332465406752.

The previous prime is 23332465406707. The next prime is 23332465406777. The reversal of 23332465406753 is 35760456423332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23252233711249 + 80231695504 = 4822057^2 + 283252^2 .

It is a cyclic number.

It is not a de Polignac number, because 23332465406753 - 210 = 23332465405729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23332465406695 and 23332465406704.

It is not a weakly prime, because it can be changed into another prime (23332465406053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11666232703376 + 11666232703377.

It is an arithmetic number, because the mean of its divisors is an integer number (11666232703377).

Almost surely, 223332465406753 is an apocalyptic number.

It is an amenable number.

23332465406753 is a deficient number, since it is larger than the sum of its proper divisors (1).

23332465406753 is an equidigital number, since it uses as much as digits as its factorization.

23332465406753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32659200, while the sum is 53.

The spelling of 23332465406753 in words is "twenty-three trillion, three hundred thirty-two billion, four hundred sixty-five million, four hundred six thousand, seven hundred fifty-three".