Base | Representation |
---|---|
bin | 1010100111010010011000… |
… | …01010000101110010110011 |
3 | 10001122021221210100000220011 |
4 | 11103221030022011302303 |
5 | 11024401041240000201 |
6 | 121350150243555351 |
7 | 4626161115413134 |
oct | 523511412056263 |
9 | 101567853300804 |
10 | 23340130000051 |
11 | 7489547a00007 |
12 | 274b58238bb57 |
13 | 1003c709105a7 |
14 | 5a994dc23c8b |
15 | 2a71e4d9e151 |
hex | 153a4c285cb3 |
23340130000051 has 2 divisors, whose sum is σ = 23340130000052. Its totient is φ = 23340130000050.
The previous prime is 23340130000009. The next prime is 23340130000087. The reversal of 23340130000051 is 15000003104332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23340130000051 - 225 = 23340096445619 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23340129999977 and 23340130000031.
It is not a weakly prime, because it can be changed into another prime (23340130000091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11670065000025 + 11670065000026.
It is an arithmetic number, because the mean of its divisors is an integer number (11670065000026).
Almost surely, 223340130000051 is an apocalyptic number.
23340130000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
23340130000051 is an equidigital number, since it uses as much as digits as its factorization.
23340130000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 23340130000051 its reverse (15000003104332), we get a palindrome (38340133104383).
The spelling of 23340130000051 in words is "twenty-three trillion, three hundred forty billion, one hundred thirty million, fifty-one", and thus it is an aban number.
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