Base | Representation |
---|---|
bin | 10101101111001111… |
… | …001111000011001001 |
3 | 2020020200101210112202 |
4 | 111233033033003021 |
5 | 340300310220012 |
6 | 14420040445545 |
7 | 1454262041615 |
oct | 255717170311 |
9 | 66220353482 |
10 | 23341101257 |
11 | 9998496931 |
12 | 4634a798b5 |
13 | 227c94ab26 |
14 | 11b5d20345 |
15 | 91923bcc2 |
hex | 56f3cf0c9 |
23341101257 has 2 divisors, whose sum is σ = 23341101258. Its totient is φ = 23341101256.
The previous prime is 23341101253. The next prime is 23341101299. The reversal of 23341101257 is 75210114332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23097616441 + 243484816 = 151979^2 + 15604^2 .
It is a cyclic number.
It is not a de Polignac number, because 23341101257 - 22 = 23341101253 is a prime.
It is a super-3 number, since 3×233411012573 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (23341101253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11670550628 + 11670550629.
It is an arithmetic number, because the mean of its divisors is an integer number (11670550629).
Almost surely, 223341101257 is an apocalyptic number.
It is an amenable number.
23341101257 is a deficient number, since it is larger than the sum of its proper divisors (1).
23341101257 is an equidigital number, since it uses as much as digits as its factorization.
23341101257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 23341101257 its reverse (75210114332), we get a palindrome (98551215589).
The spelling of 23341101257 in words is "twenty-three billion, three hundred forty-one million, one hundred one thousand, two hundred fifty-seven".
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