Base | Representation |
---|---|
bin | 1010100111010110010001… |
… | …01111010011011011010011 |
3 | 10001122111100110021122011121 |
4 | 11103223020233103123103 |
5 | 11024414331323130003 |
6 | 121351133510423111 |
7 | 4626263655261355 |
oct | 523531057233323 |
9 | 101574313248147 |
10 | 23342220130003 |
11 | 748a41a807635 |
12 | 274ba66361a97 |
13 | 1004214953a88 |
14 | 5a9aab6610d5 |
15 | 2a72b8616cbd |
hex | 153ac8bd36d3 |
23342220130003 has 2 divisors, whose sum is σ = 23342220130004. Its totient is φ = 23342220130002.
The previous prime is 23342220129971. The next prime is 23342220130037. The reversal of 23342220130003 is 30003102224332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23342220130003 - 25 = 23342220129971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 23342220130003.
It is not a weakly prime, because it can be changed into another prime (23342220130043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11671110065001 + 11671110065002.
It is an arithmetic number, because the mean of its divisors is an integer number (11671110065002).
Almost surely, 223342220130003 is an apocalyptic number.
23342220130003 is a deficient number, since it is larger than the sum of its proper divisors (1).
23342220130003 is an equidigital number, since it uses as much as digits as its factorization.
23342220130003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 23342220130003 its reverse (30003102224332), we get a palindrome (53345322354335).
The spelling of 23342220130003 in words is "twenty-three trillion, three hundred forty-two billion, two hundred twenty million, one hundred thirty thousand, three".
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