Base | Representation |
---|---|
bin | 100001111101111011100… |
… | …010111101100000110011 |
3 | 22021011002012101022022221 |
4 | 201331323202331200303 |
5 | 301221010420113042 |
6 | 4544200212141511 |
7 | 330433433443402 |
oct | 41757342754063 |
9 | 8234065338287 |
10 | 2334240004147 |
11 | 81aa446a0a77 |
12 | 318484307897 |
13 | 13c16bccc45c |
14 | 80d991c7639 |
15 | 40abb647d67 |
hex | 21f7b8bd833 |
2334240004147 has 2 divisors, whose sum is σ = 2334240004148. Its totient is φ = 2334240004146.
The previous prime is 2334240004097. The next prime is 2334240004177. The reversal of 2334240004147 is 7414000424332.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2334240004147 is a prime.
It is not a weakly prime, because it can be changed into another prime (2334240004177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1167120002073 + 1167120002074.
It is an arithmetic number, because the mean of its divisors is an integer number (1167120002074).
Almost surely, 22334240004147 is an apocalyptic number.
2334240004147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2334240004147 is an equidigital number, since it uses as much as digits as its factorization.
2334240004147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 34.
Adding to 2334240004147 its reverse (7414000424332), we get a palindrome (9748240428479).
The spelling of 2334240004147 in words is "two trillion, three hundred thirty-four billion, two hundred forty million, four thousand, one hundred forty-seven".
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