Base | Representation |
---|---|
bin | 1010100111011001100110… |
… | …01010001001000101000011 |
3 | 10001122122221212212101112002 |
4 | 11103230303022021011003 |
5 | 11024432010410103103 |
6 | 121352031010254215 |
7 | 4626356135143556 |
oct | 523546312110503 |
9 | 101578855771462 |
10 | 23344005550403 |
11 | 749015661338a |
12 | 275028428736b |
13 | 100443a80a955 |
14 | 5a9bda82069d |
15 | 2a7370240488 |
hex | 153b33289143 |
23344005550403 has 16 divisors (see below), whose sum is σ = 24386494547520. Its totient is φ = 22303813948416.
The previous prime is 23344005550351. The next prime is 23344005550429. The reversal of 23344005550403 is 30405550044332.
It is a cyclic number.
It is not a de Polignac number, because 23344005550403 - 28 = 23344005550147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23344005550303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 542395601 + ... + 542438637.
It is an arithmetic number, because the mean of its divisors is an integer number (1524155909220).
Almost surely, 223344005550403 is an apocalyptic number.
23344005550403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
23344005550403 is a deficient number, since it is larger than the sum of its proper divisors (1042488997117).
23344005550403 is a wasteful number, since it uses less digits than its factorization.
23344005550403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69166.
The product of its (nonzero) digits is 432000, while the sum is 38.
Adding to 23344005550403 its reverse (30405550044332), we get a palindrome (53749555594735).
The spelling of 23344005550403 in words is "twenty-three trillion, three hundred forty-four billion, five million, five hundred fifty thousand, four hundred three".
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