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23344023441433 = 191228632812707
BaseRepresentation
bin1010100111011001101000…
…01110011001000000011001
310001122200000010112100101211
411103230310032121000121
511024432030000111213
6121352032445543121
74626356443210162
oct523546416310031
9101580003470354
1023344023441433
117490165723162
12275028a274aa1
131004441433166
145a9bdcd5a769
152a7371ac653d
hex153b34399019

23344023441433 has 4 divisors (see below), whose sum is σ = 24572656254160. Its totient is φ = 22115390628708.

The previous prime is 23344023441383. The next prime is 23344023441499. The reversal of 23344023441433 is 33414432044332.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23344023441433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23344023441133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 614316406335 + ... + 614316406372.

It is an arithmetic number, because the mean of its divisors is an integer number (6143164063540).

Almost surely, 223344023441433 is an apocalyptic number.

It is an amenable number.

23344023441433 is a deficient number, since it is larger than the sum of its proper divisors (1228632812727).

23344023441433 is a wasteful number, since it uses less digits than its factorization.

23344023441433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1228632812726.

The product of its (nonzero) digits is 995328, while the sum is 40.

Adding to 23344023441433 its reverse (33414432044332), we get a palindrome (56758455485765).

The spelling of 23344023441433 in words is "twenty-three trillion, three hundred forty-four billion, twenty-three million, four hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 19 1228632812707 23344023441433