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23354331001 = 119983194647
BaseRepresentation
bin10101110000000001…
…101100111101111001
32020021121021221100021
4111300001230331321
5340312202043001
614421232210441
71454512352401
oct256001547571
966247257307
1023354331001
1199a4a02601
124639399a21
132282600791
1411b79a5801
1591a4a1ba1
hex57006cf79

23354331001 has 4 divisors (see below), whose sum is σ = 23354645632. Its totient is φ = 23354016372.

The previous prime is 23354330999. The next prime is 23354331029. The reversal of 23354331001 is 10013345332.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 23354331001 - 21 = 23354330999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23354331601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22660 + ... + 217306.

It is an arithmetic number, because the mean of its divisors is an integer number (5838661408).

Almost surely, 223354331001 is an apocalyptic number.

It is an amenable number.

23354331001 is a deficient number, since it is larger than the sum of its proper divisors (314631).

23354331001 is a wasteful number, since it uses less digits than its factorization.

23354331001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 314630.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 23354331001 its reverse (10013345332), we get a palindrome (33367676333).

The spelling of 23354331001 in words is "twenty-three billion, three hundred fifty-four million, three hundred thirty-one thousand, one".

Divisors: 1 119983 194647 23354331001