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23363797125553 is a prime number
BaseRepresentation
bin1010100111111110011101…
…10101000000100110110001
310001201120001012012120121221
411103333032311000212301
511030243024031004203
6121405102532345041
74630656446564053
oct523771665004661
9101646035176557
1023363797125553
117498592425765
122754088475181
131006272c6b671
145aab5716d8d3
152a7b2ca3aabd
hex153fced409b1

23363797125553 has 2 divisors, whose sum is σ = 23363797125554. Its totient is φ = 23363797125552.

The previous prime is 23363797125541. The next prime is 23363797125607. The reversal of 23363797125553 is 35552179736332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18143408402064 + 5220388723489 = 4259508^2 + 2284817^2 .

It is a cyclic number.

It is not a de Polignac number, because 23363797125553 - 217 = 23363796994481 is a prime.

It is a super-2 number, since 2×233637971255532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23363797125491 and 23363797125500.

It is not a weakly prime, because it can be changed into another prime (23363797525553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11681898562776 + 11681898562777.

It is an arithmetic number, because the mean of its divisors is an integer number (11681898562777).

Almost surely, 223363797125553 is an apocalyptic number.

It is an amenable number.

23363797125553 is a deficient number, since it is larger than the sum of its proper divisors (1).

23363797125553 is an equidigital number, since it uses as much as digits as its factorization.

23363797125553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 107163000, while the sum is 61.

The spelling of 23363797125553 in words is "twenty-three trillion, three hundred sixty-three billion, seven hundred ninety-seven million, one hundred twenty-five thousand, five hundred fifty-three".