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2340121411 = 8997271067
BaseRepresentation
bin1000101101111011…
…0110101101000011
320001002100111002101
42023132312231003
514243032341121
61024112531231
7111663463255
oct21336665503
96032314071
102340121411
11aa0a34941
12553850b17
132b3a82034
14182b13cd5
15da699491
hex8b7b6b43

2340121411 has 8 divisors (see below), whose sum is σ = 2390819760. Its totient is φ = 2289965568.

The previous prime is 2340121403. The next prime is 2340121457. The reversal of 2340121411 is 1141210432.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2340121411 - 23 = 2340121403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2340121471) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 126901 + ... + 144166.

It is an arithmetic number, because the mean of its divisors is an integer number (298852470).

Almost surely, 22340121411 is an apocalyptic number.

2340121411 is a deficient number, since it is larger than the sum of its proper divisors (50698349).

2340121411 is an equidigital number, since it uses as much as digits as its factorization.

2340121411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 271253.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 2340121411 is about 48374.8014052771. The cubic root of 2340121411 is about 1327.6373549745.

Adding to 2340121411 its reverse (1141210432), we get a palindrome (3481331843).

The spelling of 2340121411 in words is "two billion, three hundred forty million, one hundred twenty-one thousand, four hundred eleven".

Divisors: 1 89 97 8633 271067 24124963 26293499 2340121411