Base | Representation |
---|---|
bin | 110101001101010110110110… |
… | …100000010010100001100001 |
3 | 1010200120112221202120010100220 |
4 | 311031112312200102201201 |
5 | 221133042344342242403 |
6 | 2145412413253033253 |
7 | 100201656604604556 |
oct | 6515266640224141 |
9 | 1120515852503326 |
10 | 234014355040353 |
11 | 68622a26751288 |
12 | 222b5672025829 |
13 | a0765c7534b74 |
14 | 41b04d8a06a2d |
15 | 1c0c3b51d8953 |
hex | d4d5b6812861 |
234014355040353 has 4 divisors (see below), whose sum is σ = 312019140053808. Its totient is φ = 156009570026900.
The previous prime is 234014355040351. The next prime is 234014355040363. The reversal of 234014355040353 is 353040553410432.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 234014355040353 - 21 = 234014355040351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (234014355040351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39002392506723 + ... + 39002392506728.
It is an arithmetic number, because the mean of its divisors is an integer number (78004785013452).
Almost surely, 2234014355040353 is an apocalyptic number.
It is an amenable number.
234014355040353 is a deficient number, since it is larger than the sum of its proper divisors (78004785013455).
234014355040353 is an equidigital number, since it uses as much as digits as its factorization.
234014355040353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78004785013454.
The product of its (nonzero) digits is 1296000, while the sum is 42.
The spelling of 234014355040353 in words is "two hundred thirty-four trillion, fourteen billion, three hundred fifty-five million, forty thousand, three hundred fifty-three".
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