Base | Representation |
---|---|
bin | 1010101001000100100101… |
… | …10000011111010100010011 |
3 | 10001212011012212110121222220 |
4 | 11110202102300133110103 |
5 | 11031402124131411311 |
6 | 121434250332032123 |
7 | 4633461412054266 |
oct | 524422260372423 |
9 | 101764185417886 |
10 | 23401444013331 |
11 | 750255108675a |
12 | 275b434302643 |
13 | 1009992670c17 |
14 | 5ac8c9004cdd |
15 | 2a8ad2b5e206 |
hex | 154892c1f513 |
23401444013331 has 32 divisors (see below), whose sum is σ = 32203759779840. Its totient is φ = 15106557866400.
The previous prime is 23401444013329. The next prime is 23401444013357. The reversal of 23401444013331 is 13331044410432.
It is not a de Polignac number, because 23401444013331 - 21 = 23401444013329 is a prime.
It is a super-2 number, since 2×234014440133312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23401444013292 and 23401444013301.
It is not an unprimeable number, because it can be changed into a prime (23401444013131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16048230 + ... + 17445588.
It is an arithmetic number, because the mean of its divisors is an integer number (1006367493120).
Almost surely, 223401444013331 is an apocalyptic number.
23401444013331 is a deficient number, since it is larger than the sum of its proper divisors (8802315766509).
23401444013331 is a wasteful number, since it uses less digits than its factorization.
23401444013331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1398527.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 23401444013331 its reverse (13331044410432), we get a palindrome (36732488423763).
The spelling of 23401444013331 in words is "twenty-three trillion, four hundred one billion, four hundred forty-four million, thirteen thousand, three hundred thirty-one".
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