Base | Representation |
---|---|
bin | 110101001110111001010001… |
… | …110101100111000110100011 |
3 | 1010200221122202011001020212111 |
4 | 311032321101311213012203 |
5 | 221141310320310011001 |
6 | 2145533132311140151 |
7 | 100212420564603661 |
oct | 6516712165470643 |
9 | 1120848664036774 |
10 | 234120040313251 |
11 | 6866382a295024 |
12 | 22312047974657 |
13 | a08356ab571c1 |
14 | 41b5682b4bc31 |
15 | 1c0eeed5dd851 |
hex | d4ee51d671a3 |
234120040313251 has 2 divisors, whose sum is σ = 234120040313252. Its totient is φ = 234120040313250.
The previous prime is 234120040313239. The next prime is 234120040313261. The reversal of 234120040313251 is 152313040021432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 234120040313251 - 211 = 234120040311203 is a prime.
It is not a weakly prime, because it can be changed into another prime (234120040313261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117060020156625 + 117060020156626.
It is an arithmetic number, because the mean of its divisors is an integer number (117060020156626).
Almost surely, 2234120040313251 is an apocalyptic number.
234120040313251 is a deficient number, since it is larger than the sum of its proper divisors (1).
234120040313251 is an equidigital number, since it uses as much as digits as its factorization.
234120040313251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 234120040313251 its reverse (152313040021432), we get a palindrome (386433080334683).
The spelling of 234120040313251 in words is "two hundred thirty-four trillion, one hundred twenty billion, forty million, three hundred thirteen thousand, two hundred fifty-one".
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