Base | Representation |
---|---|
bin | 1010101001011010111011… |
… | …10111011011000001000011 |
3 | 10001220022011222221010210112 |
4 | 11110231131313123001003 |
5 | 11032101212013241123 |
6 | 121443553032421535 |
7 | 4634364623260523 |
oct | 524553567330103 |
9 | 101808158833715 |
10 | 23413441540163 |
11 | 75076483a9194 |
12 | 27618222478ab |
13 | 100ab5514ab1c |
14 | 5ad30657b683 |
15 | 2a9086091d78 |
hex | 154b5dddb043 |
23413441540163 has 2 divisors, whose sum is σ = 23413441540164. Its totient is φ = 23413441540162.
The previous prime is 23413441540133. The next prime is 23413441540199. The reversal of 23413441540163 is 36104514431432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23413441540163 - 216 = 23413441474627 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 23413441540163.
It is not a weakly prime, because it can be changed into another prime (23413441540133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11706720770081 + 11706720770082.
It is an arithmetic number, because the mean of its divisors is an integer number (11706720770082).
Almost surely, 223413441540163 is an apocalyptic number.
23413441540163 is a deficient number, since it is larger than the sum of its proper divisors (1).
23413441540163 is an equidigital number, since it uses as much as digits as its factorization.
23413441540163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 41.
Adding to 23413441540163 its reverse (36104514431432), we get a palindrome (59517955971595).
The spelling of 23413441540163 in words is "twenty-three trillion, four hundred thirteen billion, four hundred forty-one million, five hundred forty thousand, one hundred sixty-three".
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