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2341540113001 = 12527186919463
BaseRepresentation
bin100010000100101110101…
…010101010101001101001
322021211220221211021001221
4202010232222222221221
5301330433232104001
64551404430542041
7331112355364525
oct42045652525151
98254827737057
102341540113001
11823050393891
12319981067921
1313ca635408ab
148148c944d85
1540d974931a1
hex2212eaaaa69

2341540113001 has 4 divisors (see below), whose sum is σ = 2341727044992. Its totient is φ = 2341353181012.

The previous prime is 2341540112971. The next prime is 2341540113013. The reversal of 2341540113001 is 1003110451432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2341540113001 - 213 = 2341540104809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2341540113301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93447205 + ... + 93472258.

It is an arithmetic number, because the mean of its divisors is an integer number (585431761248).

Almost surely, 22341540113001 is an apocalyptic number.

It is an amenable number.

2341540113001 is a deficient number, since it is larger than the sum of its proper divisors (186931991).

2341540113001 is a wasteful number, since it uses less digits than its factorization.

2341540113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 186931990.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 2341540113001 its reverse (1003110451432), we get a palindrome (3344650564433).

The spelling of 2341540113001 in words is "two trillion, three hundred forty-one billion, five hundred forty million, one hundred thirteen thousand, one".

Divisors: 1 12527 186919463 2341540113001