Base | Representation |
---|---|
bin | 100010000101010000010… |
… | …010111011000100000001 |
3 | 22021220101021110122111102 |
4 | 202011100102323010001 |
5 | 301333112201022423 |
6 | 4551540423424145 |
7 | 331132346123654 |
oct | 42052022730401 |
9 | 8256337418442 |
10 | 2342104314113 |
11 | 82330a9104a3 |
12 | 319ab9bb5055 |
13 | 13cb233b3bc5 |
14 | 8150384d89b |
15 | 40dcbc8dc28 |
hex | 221504bb101 |
2342104314113 has 2 divisors, whose sum is σ = 2342104314114. Its totient is φ = 2342104314112.
The previous prime is 2342104314103. The next prime is 2342104314227. The reversal of 2342104314113 is 3114134012432.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2108324328049 + 233779986064 = 1452007^2 + 483508^2 .
It is a cyclic number.
It is not a de Polignac number, because 2342104314113 - 236 = 2273384837377 is a prime.
It is not a weakly prime, because it can be changed into another prime (2342104314103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1171052157056 + 1171052157057.
It is an arithmetic number, because the mean of its divisors is an integer number (1171052157057).
Almost surely, 22342104314113 is an apocalyptic number.
It is an amenable number.
2342104314113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2342104314113 is an equidigital number, since it uses as much as digits as its factorization.
2342104314113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 2342104314113 its reverse (3114134012432), we get a palindrome (5456238326545).
The spelling of 2342104314113 in words is "two trillion, three hundred forty-two billion, one hundred four million, three hundred fourteen thousand, one hundred thirteen".
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