Base | Representation |
---|---|
bin | 1010101001111100011000… |
… | …10110111110101110010011 |
3 | 10001222000112122122021111212 |
4 | 11110332030112332232103 |
5 | 11032400002231342003 |
6 | 121500123123330335 |
7 | 4635601653663203 |
oct | 524761426765623 |
9 | 101860478567455 |
10 | 23431401434003 |
11 | 7514224288262 |
12 | 27651b4b209ab |
13 | 100c757c78444 |
14 | 5b012b928403 |
15 | 2a9787b76dd8 |
hex | 154f8c5beb93 |
23431401434003 has 2 divisors, whose sum is σ = 23431401434004. Its totient is φ = 23431401434002.
The previous prime is 23431401433943. The next prime is 23431401434069. The reversal of 23431401434003 is 30043410413432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23431401434003 - 230 = 23430327692179 is a prime.
It is a super-2 number, since 2×234314014340032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23431407434003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11715700717001 + 11715700717002.
It is an arithmetic number, because the mean of its divisors is an integer number (11715700717002).
Almost surely, 223431401434003 is an apocalyptic number.
23431401434003 is a deficient number, since it is larger than the sum of its proper divisors (1).
23431401434003 is an equidigital number, since it uses as much as digits as its factorization.
23431401434003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 23431401434003 its reverse (30043410413432), we get a palindrome (53474811847435).
The spelling of 23431401434003 in words is "twenty-three trillion, four hundred thirty-one billion, four hundred one million, four hundred thirty-four thousand, three".
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