2343314110441 has 4 divisors (see below), whose sum is σ = 2397809787472. Its totient is φ = 2288818433412.

The previous prime is 2343314110433. The next prime is 2343314110513. The reversal of 2343314110441 is 1440114133432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2343314110441 - 2³ = 2343314110433 is a prime.

It is a super-2 number, since 2×2343314110441² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2343314111441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27247838451 + ... + 27247838536.

It is an arithmetic number, because the mean of its divisors is an integer number (599452446868).

Almost surely, 2^{2343314110441} is an apocalyptic number.

It is an amenable number.

2343314110441 is a deficient number, since it is larger than the sum of its proper divisors (54495677031).

2343314110441 is an equidigital number, since it uses as much as digits as its factorization.

2343314110441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54495677030.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 2343314110441 its reverse (1440114133432), we get a palindrome (3783428243873).

The spelling of 2343314110441 in words is "two trillion, three hundred forty-three billion, three hundred fourteen million, one hundred ten thousand, four hundred forty-one".