Base | Representation |
---|---|
bin | 1010101010001100100111… |
… | …01011111110100001111011 |
3 | 10001222212000212110102000112 |
4 | 11111012103223332201323 |
5 | 11033020323231011324 |
6 | 121504123450454535 |
7 | 4636330612145603 |
oct | 525062353764173 |
9 | 101885025412015 |
10 | 23440114313339 |
11 | 75179954a1489 |
12 | 2766a26a3444b |
13 | 10105160b9c49 |
14 | 5b0716b5dc03 |
15 | 2a9ae7a3ac0e |
hex | 155193afe87b |
23440114313339 has 2 divisors, whose sum is σ = 23440114313340. Its totient is φ = 23440114313338.
The previous prime is 23440114313281. The next prime is 23440114313351. The reversal of 23440114313339 is 93331341104432.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23440114313339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23440114313296 and 23440114313305.
It is not a weakly prime, because it can be changed into another prime (23440114313839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11720057156669 + 11720057156670.
It is an arithmetic number, because the mean of its divisors is an integer number (11720057156670).
Almost surely, 223440114313339 is an apocalyptic number.
23440114313339 is a deficient number, since it is larger than the sum of its proper divisors (1).
23440114313339 is an equidigital number, since it uses as much as digits as its factorization.
23440114313339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 41.
The spelling of 23440114313339 in words is "twenty-three trillion, four hundred forty billion, one hundred fourteen million, three hundred thirteen thousand, three hundred thirty-nine".
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