23441204014433 has 4 divisors (see below), whose sum is σ = 24674951594160. Its totient is φ = 22207456434708.

The previous prime is 23441204014363. The next prime is 23441204014463. The reversal of 23441204014433 is 33441040214432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23441204014433 - 2¹² = 23441204010337 is a prime.

It is a super-2 number, since 2×23441204014433² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23441204014393 and 23441204014402.

It is not an unprimeable number, because it can be changed into a prime (23441204014463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 616873789835 + ... + 616873789872.

It is an arithmetic number, because the mean of its divisors is an integer number (6168737898540).

Almost surely, 2^{23441204014433} is an apocalyptic number.

It is an amenable number.

23441204014433 is a deficient number, since it is larger than the sum of its proper divisors (1233747579727).

23441204014433 is a wasteful number, since it uses less digits than its factorization.

23441204014433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1233747579726.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 23441204014433 its reverse (33441040214432), we get a palindrome (56882244228865).

The spelling of 23441204014433 in words is "twenty-three trillion, four hundred forty-one billion, two hundred four million, fourteen thousand, four hundred thirty-three".