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2344143255131 = 2980832526039
BaseRepresentation
bin100010000111001001110…
…100110111011001011011
322022002122101002120202102
4202013021310313121123
5301401301133131011
64552515021154015
7331234024623266
oct42071164673133
98262571076672
102344143255131
11824166835017
1231a3889bb90b
13140089943a92
1481658563cdd
1540e9ac9473b
hex221c9d3765b

2344143255131 has 4 divisors (see below), whose sum is σ = 2424975781200. Its totient is φ = 2263310729064.

The previous prime is 2344143255101. The next prime is 2344143255137. The reversal of 2344143255131 is 1315523414432.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2344143255131 - 218 = 2344142992987 is a prime.

It is a super-2 number, since 2×23441432551312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2344143255137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40416262991 + ... + 40416263048.

It is an arithmetic number, because the mean of its divisors is an integer number (606243945300).

Almost surely, 22344143255131 is an apocalyptic number.

2344143255131 is a deficient number, since it is larger than the sum of its proper divisors (80832526069).

2344143255131 is an equidigital number, since it uses as much as digits as its factorization.

2344143255131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80832526068.

The product of its digits is 172800, while the sum is 38.

Adding to 2344143255131 its reverse (1315523414432), we get a palindrome (3659666669563).

The spelling of 2344143255131 in words is "two trillion, three hundred forty-four billion, one hundred forty-three million, two hundred fifty-five thousand, one hundred thirty-one".

Divisors: 1 29 80832526039 2344143255131