234441002414441 has 4 divisors (see below), whose sum is σ = 242003615395584. Its totient is φ = 226878389433300.

The previous prime is 234441002414393. The next prime is 234441002414449. The reversal of 234441002414441 is 144414200144432.

234441002414441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-234441002414441 is a prime.

It is a super-2 number, since 2×234441002414441² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 234441002414395 and 234441002414404.

It is not an unprimeable number, because it can be changed into a prime (234441002414449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3781306490525 + ... + 3781306490586.

It is an arithmetic number, because the mean of its divisors is an integer number (60500903848896).

Almost surely, 2^{234441002414441} is an apocalyptic number.

It is an amenable number.

234441002414441 is a deficient number, since it is larger than the sum of its proper divisors (7562612981143).

234441002414441 is an equidigital number, since it uses as much as digits as its factorization.

234441002414441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7562612981142.

The product of its (nonzero) digits is 196608, while the sum is 38.

Adding to 234441002414441 its reverse (144414200144432), we get a palindrome (378855202558873).

The spelling of 234441002414441 in words is "two hundred thirty-four trillion, four hundred forty-one billion, two million, four hundred fourteen thousand, four hundred forty-one".