Base | Representation |
---|---|
bin | 1010101010010110101010… |
… | …11110110000101101110001 |
3 | 10002000100222010020211002112 |
4 | 11111023111132300231301 |
5 | 11033112402324044213 |
6 | 121510415305455105 |
7 | 4636611446163626 |
oct | 525132536605561 |
9 | 102010863224075 |
10 | 23445513112433 |
11 | 751a205a24115 |
12 | 2767a92aa1495 |
13 | 1010b96759619 |
14 | 5b0aa9b9234d |
15 | 2a9d119b9ea8 |
hex | 1552d57b0b71 |
23445513112433 has 2 divisors, whose sum is σ = 23445513112434. Its totient is φ = 23445513112432.
The previous prime is 23445513112421. The next prime is 23445513112453. The reversal of 23445513112433 is 33421131554432.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14669420884624 + 8776092227809 = 3830068^2 + 2962447^2 .
It is a cyclic number.
It is not a de Polignac number, because 23445513112433 - 26 = 23445513112369 is a prime.
It is not a weakly prime, because it can be changed into another prime (23445513112453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11722756556216 + 11722756556217.
It is an arithmetic number, because the mean of its divisors is an integer number (11722756556217).
Almost surely, 223445513112433 is an apocalyptic number.
It is an amenable number.
23445513112433 is a deficient number, since it is larger than the sum of its proper divisors (1).
23445513112433 is an equidigital number, since it uses as much as digits as its factorization.
23445513112433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 518400, while the sum is 41.
Adding to 23445513112433 its reverse (33421131554432), we get a palindrome (56866644666865).
The spelling of 23445513112433 in words is "twenty-three trillion, four hundred forty-five billion, five hundred thirteen million, one hundred twelve thousand, four hundred thirty-three".
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