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23445513112433 is a prime number
BaseRepresentation
bin1010101010010110101010…
…11110110000101101110001
310002000100222010020211002112
411111023111132300231301
511033112402324044213
6121510415305455105
74636611446163626
oct525132536605561
9102010863224075
1023445513112433
11751a205a24115
122767a92aa1495
131010b96759619
145b0aa9b9234d
152a9d119b9ea8
hex1552d57b0b71

23445513112433 has 2 divisors, whose sum is σ = 23445513112434. Its totient is φ = 23445513112432.

The previous prime is 23445513112421. The next prime is 23445513112453. The reversal of 23445513112433 is 33421131554432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14669420884624 + 8776092227809 = 3830068^2 + 2962447^2 .

It is a cyclic number.

It is not a de Polignac number, because 23445513112433 - 26 = 23445513112369 is a prime.

It is not a weakly prime, because it can be changed into another prime (23445513112453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11722756556216 + 11722756556217.

It is an arithmetic number, because the mean of its divisors is an integer number (11722756556217).

Almost surely, 223445513112433 is an apocalyptic number.

It is an amenable number.

23445513112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23445513112433 is an equidigital number, since it uses as much as digits as its factorization.

23445513112433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 518400, while the sum is 41.

Adding to 23445513112433 its reverse (33421131554432), we get a palindrome (56866644666865).

The spelling of 23445513112433 in words is "twenty-three trillion, four hundred forty-five billion, five hundred thirteen million, one hundred twelve thousand, four hundred thirty-three".