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235013520011203 is a prime number
BaseRepresentation
bin110101011011111001011001…
…011000001010111111000011
31010211010001222021201200012101
4311123321121120022333003
5221300430142110324303
62151455415354011231
7100334111052664363
oct6533713130127703
91124101867650171
10235013520011203
116897874629043a
1222437240416b17
13a1198ab8046cb
144206a021a69a3
151c283934a8d1d
hexd5be5960afc3

235013520011203 has 2 divisors, whose sum is σ = 235013520011204. Its totient is φ = 235013520011202.

The previous prime is 235013520011189. The next prime is 235013520011239. The reversal of 235013520011203 is 302110025310532.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 235013520011203 - 213 = 235013520003011 is a prime.

It is a super-2 number, since 2×2350135200112032 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (235013520411203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117506760005601 + 117506760005602.

It is an arithmetic number, because the mean of its divisors is an integer number (117506760005602).

Almost surely, 2235013520011203 is an apocalyptic number.

235013520011203 is a deficient number, since it is larger than the sum of its proper divisors (1).

235013520011203 is an equidigital number, since it uses as much as digits as its factorization.

235013520011203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 235013520011203 its reverse (302110025310532), we get a palindrome (537123545321735).

The spelling of 235013520011203 in words is "two hundred thirty-five trillion, thirteen billion, five hundred twenty million, eleven thousand, two hundred three".