Base | Representation |
---|---|
bin | 110101011011111001011001… |
… | …011000001010111111000011 |
3 | 1010211010001222021201200012101 |
4 | 311123321121120022333003 |
5 | 221300430142110324303 |
6 | 2151455415354011231 |
7 | 100334111052664363 |
oct | 6533713130127703 |
9 | 1124101867650171 |
10 | 235013520011203 |
11 | 6897874629043a |
12 | 22437240416b17 |
13 | a1198ab8046cb |
14 | 4206a021a69a3 |
15 | 1c283934a8d1d |
hex | d5be5960afc3 |
235013520011203 has 2 divisors, whose sum is σ = 235013520011204. Its totient is φ = 235013520011202.
The previous prime is 235013520011189. The next prime is 235013520011239. The reversal of 235013520011203 is 302110025310532.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 235013520011203 - 213 = 235013520003011 is a prime.
It is a super-2 number, since 2×2350135200112032 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (235013520411203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117506760005601 + 117506760005602.
It is an arithmetic number, because the mean of its divisors is an integer number (117506760005602).
Almost surely, 2235013520011203 is an apocalyptic number.
235013520011203 is a deficient number, since it is larger than the sum of its proper divisors (1).
235013520011203 is an equidigital number, since it uses as much as digits as its factorization.
235013520011203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 235013520011203 its reverse (302110025310532), we get a palindrome (537123545321735).
The spelling of 235013520011203 in words is "two hundred thirty-five trillion, thirteen billion, five hundred twenty million, eleven thousand, two hundred three".
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