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23550443131 = 37636498463
BaseRepresentation
bin10101111011101101…
…110011111001111011
32020210021022110121111
4111323231303321323
5341212403140011
614452515421151
71462413315025
oct257355637173
966707273544
1023550443131
119a9567a546
124692bb47b7
1322b4126267
1411d5a55015
1592c7de121
hex57bb73e7b

23550443131 has 4 divisors (see below), whose sum is σ = 24186941632. Its totient is φ = 22913944632.

The previous prime is 23550443071. The next prime is 23550443143. The reversal of 23550443131 is 13134405532.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23550443131 - 213 = 23550434939 is a prime.

It is a super-2 number, since 2×235504431312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23550443093 and 23550443102.

It is not an unprimeable number, because it can be changed into a prime (23550443431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318249195 + ... + 318249268.

It is an arithmetic number, because the mean of its divisors is an integer number (6046735408).

Almost surely, 223550443131 is an apocalyptic number.

23550443131 is a deficient number, since it is larger than the sum of its proper divisors (636498501).

23550443131 is an equidigital number, since it uses as much as digits as its factorization.

23550443131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636498500.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 23550443131 its reverse (13134405532), we get a palindrome (36684848663).

The spelling of 23550443131 in words is "twenty-three billion, five hundred fifty million, four hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 37 636498463 23550443131