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239140546648753 is a prime number
BaseRepresentation
bin110110010111111100111111…
…010101011001101010110001
31011100201121112212110011021011
4312113330333111121222301
5222321034314420230003
62204335352301430521
7101241222451414621
oct6627747725315261
91140647485404234
10239140546648753
116a219a332249a2
12229a305926b441
13a358b1a488aa9
14430a66db40881
151c9a8db24646d
hexd97f3f559ab1

239140546648753 has 2 divisors, whose sum is σ = 239140546648754. Its totient is φ = 239140546648752.

The previous prime is 239140546648733. The next prime is 239140546648771. The reversal of 239140546648753 is 357846645041932.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196009436113569 + 43131110535184 = 14000337^2 + 6567428^2 .

It is a cyclic number.

It is not a de Polignac number, because 239140546648753 - 213 = 239140546640561 is a prime.

It is not a weakly prime, because it can be changed into another prime (239140546648723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 119570273324376 + 119570273324377.

It is an arithmetic number, because the mean of its divisors is an integer number (119570273324377).

It is a 2-persistent number, because it is pandigital, and so is 2⋅239140546648753 = 478281093297506, but 3⋅239140546648753 = 717421639946259 is not.

Almost surely, 2239140546648753 is an apocalyptic number.

It is an amenable number.

239140546648753 is a deficient number, since it is larger than the sum of its proper divisors (1).

239140546648753 is an equidigital number, since it uses as much as digits as its factorization.

239140546648753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 522547200, while the sum is 67.

The spelling of 239140546648753 in words is "two hundred thirty-nine trillion, one hundred forty billion, five hundred forty-six million, six hundred forty-eight thousand, seven hundred fifty-three".